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Riad Khanmagomedov's April Contest — 3rd to 10th April 201965 posts • Page 1 of 3 • 1 2 3
@ 2019-04-03 11:06 PM (#26831 - in reply to #26822) (#26831) Top

anurag



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anurag posted @ 2019-04-03 11:06 PM

Ships: As it is not mentioned on the file, I assume the fragments are pulled out straight without rotation and can be put back the same way as they are. Also, the column clues consider all 10 cells and not just the 5-cell strip.
@ 2019-04-03 11:19 PM (#26832 - in reply to #26822) (#26832) Top

anurag



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anurag posted @ 2019-04-03 11:19 PM

Distyle: these puzzles usually do not allow 2x2 squares of shaded cells (except paint by number). What about this one? There is no mention.
Solving the example does not help deuce the rule either way as it can be solved uniquely without having to consider 2x2 squares.

Edited by anurag 2019-04-03 11:31 PM
@ 2019-04-04 5:01 AM (#26833 - in reply to #26822) (#26833) Top

kiwijam



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kiwijam posted @ 2019-04-04 5:01 AM

Pentocolour:
1) Can a black pentomino diagonally touch an orange pentomino with the same letter?
2) Please explain how to calculate K. In mathematics, two different-sized squares are 'similar'. Is this the count of different white shapes (different after rotation and reflection)? So if I have a horizontal white domino and a vertical white domino, then K=1?
@ 2019-04-04 2:09 PM (#26834 - in reply to #26827) (#26834) Top

Riad Khanmagomedov



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Riad Khanmagomedov posted @ 2019-04-04 2:09 PM

Puzlifouk - 2019-04-03 11:13 AM

Hello everybody,
Is it good for today? I'm so impatient: I took my leave for that.

I wish you success!
@ 2019-04-04 2:10 PM (#26835 - in reply to #26831) (#26835) Top

Riad Khanmagomedov



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Riad Khanmagomedov posted @ 2019-04-04 2:10 PM

anurag - 2019-04-03 11:06 PM

Ships: As it is not mentioned on the file, I assume the fragments are pulled out straight without rotation and can be put back the same way as they are. Also, the column clues consider all 10 cells and not just the 5-cell strip.

Ships can be rotated. The column clues consider all 10 cells.
@ 2019-04-04 2:10 PM (#26836 - in reply to #26832) (#26836) Top

Riad Khanmagomedov



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Riad Khanmagomedov posted @ 2019-04-04 2:10 PM

anurag - 2019-04-03 11:19 PM

Distyle: these puzzles usually do not allow 2x2 squares of shaded cells (except paint by number). What about this one? There is no mention.
Solving the example does not help deuce the rule either way as it can be solved uniquely without having to consider 2x2 squares.

The 2 x 2 squares can be shaded.
@ 2019-04-04 2:11 PM (#26837 - in reply to #26833) (#26837) Top

Riad Khanmagomedov



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Riad Khanmagomedov posted @ 2019-04-04 2:11 PM

kiwijam - 2019-04-04 5:01 AM

Pentocolour:
1) Can a black pentomino diagonally touch an orange pentomino with the same letter?
2) Please explain how to calculate K. In mathematics, two different-sized squares are 'similar'. Is this the count of different white shapes (different after rotation and reflection)? So if I have a horizontal white domino and a vertical white domino, then K=1?

1) No.
2) If there are several white dominoes in the grid, then K=1. If several different white triminoes, then K=2. White square 1 x 1 and white square 2 x 2 - different shapes, K=2.
If you still have doubts about the translation, I am ready to comment.
@ 2019-04-04 2:20 PM (#26838 - in reply to #26822) (#26838) Top

Léotte



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Léotte posted @ 2019-04-04 2:20 PM

At the levers : can you check for the solution? I may be mistaken (of course!), but I really see no solution here :/
@ 2019-04-04 2:54 PM (#26839 - in reply to #26835) (#26839) Top

anurag



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anurag posted @ 2019-04-04 2:54 PM

No, not ships. I was asking about the 5x10 fragments. But nevermind, I solved it. It was fun.
@ 2019-04-04 9:22 PM (#26840 - in reply to #26839) (#26840) Top

Administrator



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Administrator posted @ 2019-04-04 9:22 PM

Submission page


The Submission page is now ready: http://logicmastersindia.com/2019/04Contest/

You can submit your answer keys now. There is no instant grading in this test.

(Potential) Results link shows possible points based on submissions, even if incorrect.

Some of the answer keys (mainly for Optimizers) may show red validation messages. They can be ignored if you think your answer key is right.

Submissions should be completed by 10th April midnight (Moscow time).

@ 2019-04-04 10:05 PM (#26841 - in reply to #26822) (#26841) Top

Puzlifouk



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Puzlifouk posted @ 2019-04-04 10:05 PM

A remark about Magic Tapa : because we always have R>=r and C>=c, minimizing (|R-r|-r + |C-c|-c) is always exactly the same thing than minimizing (R-2r+C-2c). Right?
@ 2019-04-04 11:47 PM (#26842 - in reply to #26841) (#26842) Top

anurag



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anurag posted @ 2019-04-04 11:47 PM

ROFL.. you are right. That's a print error. Perhaps it was intended like this: the closing pipe comes after the third 'r'. |R-r-r| + C-c-c|
@ 2019-04-05 3:47 AM (#26843 - in reply to #26822) (#26843) Top

kiwijam



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kiwijam posted @ 2019-04-05 3:47 AM

At The Levers: Does the small example have two solutions? When I put "3-3" on the diagonal lever it also works, or is this not allowed?
@ 2019-04-05 9:32 AM (#26844 - in reply to #26841) (#26844) Top

anurag



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anurag posted @ 2019-04-05 9:32 AM

It appears the objective here is to maximize the row min and column min, as also indicated by the revealing title. Maximize (r+c) could be a simpler scoring formula.
@ 2019-04-05 1:07 PM (#26845 - in reply to #26843) (#26845) Top

L00ping007



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L00ping007 posted @ 2019-04-05 1:07 PM

kiwijam - 2019-04-04 11:47 PM

At The Levers: Does the small example have two solutions? When I put "3-3" on the diagonal lever it also works, or is this not allowed?


I agree, the 2 solutions work for me

Léotte - 2019-04-04 10:20 AM

At the levers : can you check for the solution? I may be mistaken (of course!), but I really see no solution here :/


Same for me ... My step by step logic way leads to a dead end


Do we miss something here ?
@ 2019-04-05 2:10 PM (#26846 - in reply to #26838) (#26846) Top

Riad Khanmagomedov



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Riad Khanmagomedov posted @ 2019-04-05 2:10 PM

Léotte - 2019-04-04 2:20 PM

At the levers : can you check for the solution? I may be mistaken (of course!), but I really see no solution here :/

4 testers solved this puzzle.
@ 2019-04-05 2:11 PM (#26847 - in reply to #26841) (#26847) Top

Riad Khanmagomedov



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Riad Khanmagomedov posted @ 2019-04-05 2:11 PM

Puzlifouk - 2019-04-04 10:05 PM

A remark about Magic Tapa : because we always have R>=r and C>=c, minimizing (|R-r|-r + |C-c|-c) is always exactly the same thing than minimizing (R-2r+C-2c). Right?

Convert the expression as you like.
@ 2019-04-05 2:11 PM (#26848 - in reply to #26842) (#26848) Top

Riad Khanmagomedov



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Riad Khanmagomedov posted @ 2019-04-05 2:11 PM

anurag - 2019-04-04 11:47 PM

ROFL.. you are right. That's a print error. Perhaps it was intended like this: the closing pipe comes after the third 'r'. |R-r-r| + C-c-c|

There is no printer error. Some of the puzzles I've made in 2015 and corrected in 2019. I modified the problem, but the expression is correct.
@ 2019-04-05 2:12 PM (#26849 - in reply to #26843) (#26849) Top

Riad Khanmagomedov



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Riad Khanmagomedov posted @ 2019-04-05 2:12 PM

kiwijam - 2019-04-05 3:47 AM

At The Levers: Does the small example have two solutions? When I put "3-3" on the diagonal lever it also works, or is this not allowed?

Thanks for the comment, I'll correct the example.
@ 2019-04-05 2:38 PM (#26850 - in reply to #26848) (#26850) Top

anurag



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anurag posted @ 2019-04-05 2:38 PM

Strange. Are you saying sub-zero scores are valid and considered as more rewarding than a score of 0?
@ 2019-04-05 3:13 PM (#26851 - in reply to #26822) (#26851) Top

kiwijam



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kiwijam posted @ 2019-04-05 3:13 PM

Anurag, please show respect to Riad, I'm much enjoying the effort he has done for this competition.
I think the Magic Tapa expression is clear and makes sense as it is (range minus minimum). As he says, you can maximize whatever you like but the final scores will be based on the official expression.
And yes, a score of -1 would be better than a score of 0 if you can achieve that. If there are other negative scores then the most negative score would be the best.
@ 2019-04-05 4:45 PM (#26852 - in reply to #26822) (#26852) Top

Puzlifouk



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Puzlifouk posted @ 2019-04-05 4:45 PM

I do not know what "score" you are talking about when you say "And yes, a score of -1 would be better than a score of 0 if you can achieve that. If there are other negative scores then the most negative score would be the best."
If the score is the final score to maximize (that is | R-r | -r + | C-c | -c), then personally I have never seen that -1> 0 nor -10 > -5 !?! ... But you are free: as you say the expression is clear, everybody will interpret as he wants.
@ 2019-04-05 5:13 PM (#26853 - in reply to #26852) (#26853) Top

anurag



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anurag posted @ 2019-04-05 5:13 PM

That's Correct and clears the doubt, at least for some.
The whole purpose of asking questions is to be able to complete the set and I am sure puzzle solving is not an objectionable activity. For any unrelated suggestions/objections, I believe personal emails are a better medium.
@ 2019-04-05 6:08 PM (#26854 - in reply to #26842) (#26854) Top

Administrator



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Administrator posted @ 2019-04-05 6:08 PM

anurag - 2019-04-04 11:47 PM

ROFL..
We request everyone to please stick to "English" on this forum. Thanks.
@ 2019-04-05 6:39 PM (#26855 - in reply to #26831) (#26855) Top

3strikerz



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3strikerz posted @ 2019-04-05 6:39 PM

anurag - 2019-04-03 11:06 PM

Ships: As it is not mentioned on the file, I assume the fragments are pulled out straight without rotation and can be put back the same way as they are. Also, the column clues consider all 10 cells and not just the 5-cell strip.


Probably everyone might have understood the puzzle description, but since I didn't and need some clarification;

A)Is the red clues in the 5x10 fragments intended to be solved as 5x10 battleship clues, or is the red clues the equivalent of 10x10 original battleship clues?

B)Is it okay for ships to be 'fragmented' in the 5x10 clues?
Riad Khanmagomedov's April Contest — 3rd to 10th April 201965 posts • Page 1 of 3 • 1 2 3
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