![]() | |
![]() ![]() ![]() ![]() ![]() Country : India | Administrator posted @ 2012-11-06 5:44 AM With no more participants, Fugitive Warrant is now over. Password removed from pdf. |
![]() | |
Posts: 25 ![]() Country : South Korea | Kwaka posted @ 2012-11-06 6:12 AM Thanks for enjoying our test. It was very good experience to be an author of LMI test. Next time I'll consider more about size of puzzle. ![]() Also, few more things. Little Multiplication Killer : First time, there is no given number inside of the grid. It can be still solvable without it. Little Killer with ER : Also, the number in R9C1 which is 7 was not given first time. It can be still solvable without it. (But one can know the sum of R9C1 and R1C9 using the sum of remainders which I saw at the test 'Killer Shootout'. ) Last, I have a few questions. How do you make a 'nonconsecutive sudoku' ? Do you use a solution which is easily gotten from other problems, or just use a computer when you make it? Same question for 'Antiknight', 'Untouch'. ![]() Somebody help me to improve my ability to make. Kwak Edited by Kwaka 2012-11-06 6:13 AM |
![]() | |
![]() ![]() ![]() ![]() ![]() Country : India | Administrator posted @ 2012-11-06 8:51 AM Congratulations to Kota for his win. It is hard to believe that this his first win in an LMI test, but he has been in top 3 in each of last 7 sudoku tests, except one. |
![]() | |
Posts: 31 ![]() Country : United States | joshuazucker posted @ 2012-11-06 10:42 AM I would love some solution tips on the weighted killer. I did eventually get it but it took me a very long time! |
![]() | |
![]() ![]() ![]() ![]() ![]() Country : India | Administrator posted @ 2012-11-06 2:33 PM Link to Solutions booklet |
![]() | |
Posts: 3 Country : South Korea | Spica posted @ 2012-11-06 9:02 PM joshuazucker// Thanks for enjoy our Sudokus. Weighted Killer(Spoiler!!) : See http://home.postech.ac.kr/~meso/sudoku/weighted_killer.html When I made this problem, Kwaka found that solution route very quickly. That's why we give (relatively) low points on this hard problem. Sorry for that ![]() Spoiler: show Once you add the cages at two bottom rows(with additional cell R7C8), then you can get the clue. Since R8C5 and R8C6 can not be both 1 at the same time, the sum 96 is the minimum possible value. Hence R9C1 = R7C8 = 1 and we have a multiple set {R8C5, R8C6} = {1,2}. That is the starting point I intended. If it is not enough, the sum of first row also gives you many informations. |
![]() | |
Posts: 31 ![]() Country : United States | joshuazucker posted @ 2012-11-07 1:56 AM Yeah, I got stuck after finding the 389 in the middle of the top and finding the shaded 1s and 2s in the bottom rows ... what next? |
![]() | |
Posts: 3 Country : South Korea | Spica posted @ 2012-11-07 6:48 AM |
![]() | |
Posts: 31 ![]() Country : United States | joshuazucker posted @ 2012-11-07 9:02 AM Thanks for all the help! You're still earlier in the solve than the spot where it got hard for me. |