@ 2012-11-06 6:12 AM (#8923 - in reply to #8828) (#8923) Top | |
Posts: 25 Country : South Korea | Kwaka posted @ 2012-11-06 6:12 AM Thanks for enjoying our test. It was very good experience to be an author of LMI test. Next time I'll consider more about size of puzzle. Also, few more things. Little Multiplication Killer : First time, there is no given number inside of the grid. It can be still solvable without it. Little Killer with ER : Also, the number in R9C1 which is 7 was not given first time. It can be still solvable without it. (But one can know the sum of R9C1 and R1C9 using the sum of remainders which I saw at the test 'Killer Shootout'. ) Last, I have a few questions. How do you make a 'nonconsecutive sudoku' ? Do you use a solution which is easily gotten from other problems, or just use a computer when you make it? Same question for 'Antiknight', 'Untouch'. Somebody help me to improve my ability to make. Kwak Edited by Kwaka 2012-11-06 6:13 AM |
@ 2012-11-06 8:51 AM (#8924 - in reply to #8828) (#8924) Top | |
Country : India | Administrator posted @ 2012-11-06 8:51 AM Congratulations to Kota for his win. It is hard to believe that this his first win in an LMI test, but he has been in top 3 in each of last 7 sudoku tests, except one. |
@ 2012-11-06 10:42 AM (#8928 - in reply to #8828) (#8928) Top | |
Posts: 31 Country : United States | joshuazucker posted @ 2012-11-06 10:42 AM I would love some solution tips on the weighted killer. I did eventually get it but it took me a very long time! |
@ 2012-11-06 2:33 PM (#8929 - in reply to #8828) (#8929) Top | |
Country : India | Administrator posted @ 2012-11-06 2:33 PM Link to Solutions booklet |
@ 2012-11-06 9:02 PM (#8930 - in reply to #8928) (#8930) Top | |
Posts: 3 Country : South Korea | Spica posted @ 2012-11-06 9:02 PM joshuazucker// Thanks for enjoy our Sudokus. Weighted Killer(Spoiler!!) : See http://home.postech.ac.kr/~meso/sudoku/weighted_killer.html When I made this problem, Kwaka found that solution route very quickly. That's why we give (relatively) low points on this hard problem. Sorry for that Spoiler: show Once you add the cages at two bottom rows(with additional cell R7C8), then you can get the clue. Since R8C5 and R8C6 can not be both 1 at the same time, the sum 96 is the minimum possible value. Hence R9C1 = R7C8 = 1 and we have a multiple set {R8C5, R8C6} = {1,2}. That is the starting point I intended. If it is not enough, the sum of first row also gives you many informations. |
@ 2012-11-07 1:56 AM (#8931 - in reply to #8930) (#8931) Top | |
Posts: 31 Country : United States | joshuazucker posted @ 2012-11-07 1:56 AM Yeah, I got stuck after finding the 389 in the middle of the top and finding the shaded 1s and 2s in the bottom rows ... what next? |
@ 2012-11-07 6:48 AM (#8935 - in reply to #8931) (#8935) Top | |
Posts: 3 Country : South Korea | Spica posted @ 2012-11-07 6:48 AM |
@ 2012-11-07 9:02 AM (#8936 - in reply to #8828) (#8936) Top | |
Posts: 31 Country : United States | joshuazucker posted @ 2012-11-07 9:02 AM Thanks for all the help! You're still earlier in the solve than the spot where it got hard for me. |