@ 2012-11-06 10:42 AM (#8928 - in reply to #8828) (#8928) Top | |
Posts: 31 Country : United States | joshuazucker posted @ 2012-11-06 10:42 AM I would love some solution tips on the weighted killer. I did eventually get it but it took me a very long time! |
@ 2012-11-06 2:33 PM (#8929 - in reply to #8828) (#8929) Top | |
Country : India | Administrator posted @ 2012-11-06 2:33 PM Link to Solutions booklet |
@ 2012-11-06 9:02 PM (#8930 - in reply to #8928) (#8930) Top | |
Posts: 3 Country : South Korea | Spica posted @ 2012-11-06 9:02 PM joshuazucker// Thanks for enjoy our Sudokus. Weighted Killer(Spoiler!!) : See http://home.postech.ac.kr/~meso/sudoku/weighted_killer.html When I made this problem, Kwaka found that solution route very quickly. That's why we give (relatively) low points on this hard problem. Sorry for that Spoiler: show Once you add the cages at two bottom rows(with additional cell R7C8), then you can get the clue. Since R8C5 and R8C6 can not be both 1 at the same time, the sum 96 is the minimum possible value. Hence R9C1 = R7C8 = 1 and we have a multiple set {R8C5, R8C6} = {1,2}. That is the starting point I intended. If it is not enough, the sum of first row also gives you many informations. |
@ 2012-11-07 1:56 AM (#8931 - in reply to #8930) (#8931) Top | |
Posts: 31 Country : United States | joshuazucker posted @ 2012-11-07 1:56 AM Yeah, I got stuck after finding the 389 in the middle of the top and finding the shaded 1s and 2s in the bottom rows ... what next? |
@ 2012-11-07 6:48 AM (#8935 - in reply to #8931) (#8935) Top | |
Posts: 3 Country : South Korea | Spica posted @ 2012-11-07 6:48 AM |
@ 2012-11-07 9:02 AM (#8936 - in reply to #8828) (#8936) Top | |
Posts: 31 Country : United States | joshuazucker posted @ 2012-11-07 9:02 AM Thanks for all the help! You're still earlier in the solve than the spot where it got hard for me. |