Posts: 1943 ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() Country : India | prasanna16391 posted @ 2026-02-12 4:37 AM ![]() Link for rules and other details about Puzzle Ramayan: http://logicmastersindia.com/PR/2026pr.asp The Instruction Booklet is now available on the submission page - https://logicmastersindia.com/live/?contest=PR202602 The round will have a Friday night start instead of the usual Thursday night. |
@ 2026-02-12 4:46 AM (#38223 - in reply to #38222) (#38223) Top | |
Posts: 1943 ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() Country : India | prasanna16391 posted @ 2026-02-12 4:46 AM The Instruction Booklet has been published. Please note any issues here, they'll be addressed by the second version. |
@ 2026-02-12 1:26 PM (#38231 - in reply to #38222) (#38231) Top | |
Posts: 54 ![]() ![]() Country : India | ABcDexter posted @ 2026-02-12 1:26 PM If I understand the rules of Bhai Bahan correctly, if a circle has clue N with the segment doing a 90 degrees turns , then there needs to be N orthogonally connected cells also doing 90 degree turns in that segment before it goes straight through any other cell. Correct? And the same goes for for the other type of clues (Bahan) |
@ 2026-02-12 10:22 PM (#38250 - in reply to #38222) (#38250) Top | |
Posts: 1 Country : United Arab Emirates | klic posted @ 2026-02-12 10:22 PM Yes |
@ 2026-02-13 12:17 AM (#38253 - in reply to #38231) (#38253) Top | |
Posts: 1943 ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() Country : India | prasanna16391 posted @ 2026-02-13 12:17 AM ABcDexter - 2026-02-12 1:26 PM If I understand the rules of Bhai Bahan correctly, if a circle has clue N with the segment doing a 90 degrees turns , then there needs to be N orthogonally connected cells also doing 90 degree turns in that segment before it goes straight through any other cell. Correct? And the same goes for for the other type of clues (Bahan) The cell itself is counted so there will be N-1 other cells that also have turns in that segment, and once the turns are done it has to go straight on both sides at least one cell to "break" the segment. |