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Posts: 87 ![]() ![]() ![]() ![]() Country : India | harmeet posted @ 2015-06-25 2:26 PM Because R1C7 will be 3, thereby forcing R2C2 to be 3. I'm only going by the image you posted with the marks. Yet to try and solve the sudoku. |
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Posts: 419 ![]() ![]() ![]() ![]() Country : India | kishy72 posted @ 2015-06-25 2:37 PM harmeet - 2015-06-25 2:26 PM Because R1C7 will be 3, thereby forcing R2C2 to be 3. I'm only going by the image you posted with the marks. Yet to try and solve the sudoku. Yes.Now it's clear.I was not able to follow what you said earlier.I don't think we need to go down to boxes 6,9 etc., for proving that contradiction.So the logic is that if there is a 2 in R2C8 ,then 1 and 3 will be cramped for space in Box 1. Great work and some good spotting!Well done!! Thanks a lot ! Kishore |
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Posts: 87 ![]() ![]() ![]() ![]() Country : India | harmeet posted @ 2015-06-25 2:37 PM Yeah you said it yourself. If R2C8 is 2 then there cannot be 1 anywhere in R2. Hence R2C8 must be 1. |
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Posts: 419 ![]() ![]() ![]() ![]() Country : India | kishy72 posted @ 2015-06-25 2:48 PM harmeet - 2015-06-25 2:37 PM Yeah you said it yourself. If R2C8 is 2 then there cannot be 1 anywhere in R2. Hence R2C8 must be 1. No!!You are getting me wrong.I said that if R2C8 is 2 ,then 1 cannot be anywhere in R2 EXCEPT R2C2. BUT it doesn't work that way! I came to know the logic after your second post where you mentioned that if R2C8 is 2 then R1C7 is 3 .Continuing on this line of thinking we have the following : If R2C8 is 2 ---->R1C7 is 3 ---->R2 (C7/C9) will be 45 and 457 respectively ---->Now looking at R2,there is a triplet 457 ,45 and 457 --->1 and 3 can only be in Box 1 which cannot be the case obviously looking at the image ---->Therefore 2 is not at R2C8 and 1 is the digit. |
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Posts: 52 ![]() ![]() Country : India | gaurav.kjain posted @ 2015-07-05 7:11 PM |
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Posts: 157 ![]() ![]() ![]() Country : India | akash.doulani posted @ 2015-07-05 9:44 PM R7c6 will be 5 because of BUG |
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Posts: 52 ![]() ![]() Country : India | gaurav.kjain posted @ 2015-07-06 8:21 AM akash.doulani - 2015-07-05 9:44 PM R7c6 will be 5 because of BUG Thanks Akash. I would want to see more logical opening. Appreciate anyone help. |
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Posts: 1800 ![]() ![]() ![]() ![]() ![]() Country : India | prasanna16391 posted @ 2015-07-06 9:42 AM If 6 is in R9C2, using 4th box, it can't be in R6C5. If 5 is in R9C6, using 2nd box, it can't be in R6C5. Reading both of those together should show that the placements together force no digit in R6C5. |
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Posts: 739 ![]() ![]() ![]() ![]() Country : India | vopani posted @ 2015-07-06 10:45 AM @Akash Seems like you found a bug in this sudoku! ;-) @Gaurav Why do you want to see a more logical opening? What is your intention behind it? What is it that you will gain by learning about Swordfish or BUG or any of these extremely advanced techniques? |
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Posts: 1800 ![]() ![]() ![]() ![]() ![]() Country : India | prasanna16391 posted @ 2015-07-06 10:53 AM Rohan Rao - 2015-07-06 10:45 AM @Gaurav Why do you want to see a more logical opening? What is your intention behind it? What is it that you will gain by learning about Swordfish or BUG or any of these extremely advanced techniques? Fair point. In a competition at this stage I would always prefer T&E. |
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Posts: 52 ![]() ![]() Country : India | gaurav.kjain posted @ 2015-07-06 11:01 PM prasanna16391 - 2015-07-06 9:42 AM If 6 is in R9C2, using 4th box, it can't be in R6C5. If 5 is in R9C6, using 2nd box, it can't be in R6C5. Reading both of those together should show that the placements together force no digit in R6C5. Thanks Prasanna. |
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Posts: 419 ![]() ![]() ![]() ![]() Country : India | kishy72 posted @ 2015-09-08 12:03 PM A Consecutive Sudoku from the US Sudoku Team Qualification round by Wei-Hwa Huang.I greatly enjoyed this very delightful set ! All the sudokus had a unique solve path and were beautifully constructed.I was more or less sprinting through the test when I hit this one and spent around 27-28 mins on this single sudoku.I adopted a very mechanical approach and found that R2C6 was the start in my case.I eliminated digits one by one in R2C6 which was very tiresome.Surely, there must be an alternative easier solve than the one mentioned.If someone has a better start,please let me know..... ![]() Kishore Edited by kishy72 2015-09-08 12:03 PM |
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Posts: 1800 ![]() ![]() ![]() ![]() ![]() Country : India | prasanna16391 posted @ 2015-09-08 4:33 PM What I did was, 1. Mark odds/evens. In 2nd box, there are three distinct consecutive pairs, which would take one odd and one even each, meaning two odds and one even go in the series of 3. The series of 3 cannot have 7 and so cannot have 9 either and so must be 123 or 345. Either way, 3 is part of it, and there must be groups of 6-7 and 8-9 in that box elsewhere. 2. Then, note that R3C8 to R3C7 is a series of 6 and that R1C7 = R2C6. 3. Where can 8 be in the 3rd box? Can't be in R1C8 because that is odd (using C8). Can't be in R1C7 or R2C7 because both are 3rd/4th cells of a 6-cell series (considering R1C7=R2C6. 8 cannot be in R2C8 either because that causes a 5-6 pair in 2nd box which isn't allowed going by step 1. So, 8 is at an extreme of the 6-cell series. 4. The series has to be 8-7-6-5-4-3 or 3-4-5-6-7-8. Either way, R1C7, R2C7 will form a 5-6 pair, which means 7 cannot be in R2C9 or R3C9 because 6 is taken. So, 7 must be in R2C7 and the series of 6 is done. (Consecutive.png) Attachments ---------------- ![]() |
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Posts: 419 ![]() ![]() ![]() ![]() Country : India | kishy72 posted @ 2015-09-08 6:25 PM prasanna16391 - 2015-09-08 4:33 PM What I did was, 1. Mark odds/evens. For reasons unknown,I fail to use this simple yet highly powerful notation.Now,I clearly understand where I am missing the trick in this variant of sudoku.Often it is the consecutive sudoku that tends to trip me up a lot in any test.Just like the in/out rule of an irregular,I am beginning to comprehend that this notation of odd/even is indispensable when it comes to consecutive and possibly a lot other variants. Can't be in R1C7 or R2C7 because both are 3rd/4th cells of a 6-cell series I never spotted this 6-cell series and I never would have if it hadn't been for the explanation you gave.This is mainly due to the fact that the series bends back on itself.I was under the impression that it leads to additional possibilities rather than a straight 6-cell consecutive chain.I am curious to know whether you spotted it right away?If yes,what made you sure that it is a series of straight 6 consecutive numbers ? and thanks a ton for the lovely explanation and for making me a better solver right from this moment ! Kishore |
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Posts: 1800 ![]() ![]() ![]() ![]() ![]() Country : India | prasanna16391 posted @ 2015-09-08 8:24 PM Because of the converse rule, a 'T' shape of consecutive bars will always be a series of 4. The series in question clearly extends on the T since the R2C7 continuation to R2C8 cannot be the same as R2C6. I also notice a series of 8 in the bottom left btw, but didn't use that till later. The series of 8 is a bit more difficult to see, but note that R7C3 is the intersection of two T-shapes, so if it is the same series going outward from there then the same digit will be in R6C2 and R8C3. |
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Posts: 419 ![]() ![]() ![]() ![]() Country : India | kishy72 posted @ 2015-09-08 8:52 PM Thank you.That makes it clear! |
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Posts: 10 Country : India | abhi265645 posted @ 2015-09-16 7:43 PM Not been able to move after this... Please help. TIA<a href="http://tinypic.com?ref=32zjnma" target="_blank"><img src="http://i60.tinypic.com/32zjnma.jpg" border="0" alt="Image and video hosting by TinyPic"></a> |
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Posts: 668 ![]() ![]() ![]() ![]() ![]() Country : India | swaroop2011 posted @ 2015-09-16 8:32 PM I think last row, 1 will come at C3. |
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Posts: 10 Country : India | abhi265645 posted @ 2015-09-17 11:58 AM Thank you @Swaroop. |
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Posts: 419 ![]() ![]() ![]() ![]() Country : India | kishy72 posted @ 2015-09-24 6:59 PM |
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Posts: 52 ![]() ![]() Country : India | gaurav.kjain posted @ 2015-09-24 10:29 PM Some cells are divided into GROUP A and B and possible Group positions are marked. 'A' group 2 cells should be same as 'A' middle cell group and 'B' group cells in Box2 should become part of B group cells in marked positions. B connections are shown, so because of that B group cells as shown connected, with violet colour should be same ![]() |
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Posts: 419 ![]() ![]() ![]() ![]() Country : India | kishy72 posted @ 2015-09-24 10:51 PM Thanks!!Was difficult to spot.I could get only the A group .Now I see what I missed. Kishore |
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Posts: 52 ![]() ![]() Country : India | gaurav.kjain posted @ 2015-09-25 11:39 AM Cross number sudoku, Either I didnot understand the rules or there is serious error in Cross Numbers marking, round represent cross number marking, you can check column 5 [1 1 1] is not satisfied. Someone please help. ![]() imag |
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Posts: 419 ![]() ![]() ![]() ![]() Country : India | kishy72 posted @ 2015-09-25 12:32 PM gaurav.kjain - 2015-09-25 11:39 AM Cross number sudoku, Either I didnot understand the rules or there is serious error in Cross Numbers marking, round represent cross number marking, you can check column 5 [1 1 1] is not satisfied. Someone please help. This is how the crossword goes.See where you have gone wrong. ![]() |
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Posts: 52 ![]() ![]() Country : India | gaurav.kjain posted @ 2015-09-25 12:42 PM Ohh this R6c6/7 and R7C6/7 creating 2x2 which I was thinking no 2x2 is possible in cross number, This was my confusion and this was prohibiting me from putting any more markings. Thanks Kishore Please give me some starting steps for wall sudoku. kishy72 - 2015-09-25 12:32 PM gaurav.kjain - 2015-09-25 11:39 AM Cross number sudoku, Either I didnot understand the rules or there is serious error in Cross Numbers marking, round represent cross number marking, you can check column 5 [1 1 1] is not satisfied. Someone please help. This is how the crossword goes.See where you have gone wrong. ![]() |