Hi
my printer does not recognize the internal grid lines of the TOOLS. something similar happened at the beginning of the marathon with the fillomino diagram. the inside of the diagram is completely blank. can somebody fix it?
Thanks
stefano

Hi Stefano,
Riad made this grid with solid lines. Please check.



Attachments
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April_Contest_2015_TOOLS.pdf (58KB - 12 downloads)

yes it works, thank you
sf

re. puzzle 10. can additional letters be included in the sequence, example APRI5L CONTEST 2015 AT LMTI?

To follow up on the previous question. Is it allowed to make the crossings on the cells with the letters? In that case, if the letter has remained out of the loop, is it an empty cell?

Hello. Very pleasant contest : I like !
For puzzle 11, the answer is controlled as "- or number (10 times)" but the grid is 11x11 : so I suppose it would be "- or number (11 times)" ?

You are right. Fixed the warning.

I have the same question. For example, along the line we must go through two letters 'A' : is it possible to go through the same letter 'A' 2 times (by crossing), and to avoid the second letter 'A' ?

No Stefano,
This is unacceptable.

The line should pass through each letter. The letter can not be remained out of the loop.

Perhaps such conditions would make the puzzle more difficult. But I assumed that the line goes through all the characters.

In the answering form, for puzzle 11, I think the answer keys need to be of length 11 not 10 as claimed by the format verification code (which warns me that my answer keys are not of the right length).

(In general, many of the answer keys seem trickier than necessary -- really, counting the C's? diagonals that go in the opposite of the usual direction? --, but it's too late to change them).

I'm a pronounced left-handed. Maybe because I offered unusual diagonals?

About puzzle 10 (APRIL CONTEST 2015 AT LMI):
It is not necessary for the line to start at cells with A and end at cells with I.

Hello. New question : in Sudoku without wall, may a wall segment separate two cells of the same area ?

Hello, certainly not!

#@!%^

????????????, ????! ??????? ?? ?????????? ???????.

4. ???????????? ??????.
????? ?????? ???????? ???????, ? ??????? ??? ??????, ????? ? ??????? ????????? ?????????? ? ???? ??? ? ?????? ?????.

1.????? ??, ??? ?????? ????? ? ??????? ?????? ???? ?? ??? ????????? ? ??????????????? ???????? ??? ??????? ?????????? ???? ? 2 ? 0, 2 ? 0 ? ?????????? ???????, ?? ?? ????????????. ????? ?? ? ???????????? ???? ???? 2 ? 5 - ??? ????????? "???????" ???????????
2. ????? ????? ?? ????? ???? ? ?????????? ?? ???????? ????????, 2 ? 5 ????? ??? ????

Zdravstvujte, Riad! Spasibo za interesnye zadanija.

4. ZAZERKAL''NYE SUDOKU.
Serym cvetom otmecheny zerkala, a zeljonym vse kletki, cifry v kotoryh zerkal'no otrazhajutsja v sebja ili v drugie cifry.

1.Verno li, chto kazhdaja cifra v zeljonoj kletke HOTJa BY RAZ otrzhaetsja v sootvetstvujushhej zeljonoj? Kak primere vnutrennie ugly s 2 i 0, 2 i 0 v zerkal'nyh zeljonyh, no ne povtorjajut'sja. Mogut li v edinstvennoj pare byt' 2 i 5 - jeto schitaetsja "zeljonym" otrazheniem?
2. Kakie cifry NE MOGUT BYT'' v zerkal'nyh NE ZELJoNYH? Naprimer, 2 i 5 mogut ili net?

Edited by Mihalich 2015-04-07 11:44 AM






Attachments
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Mihalich_Post18193.png (17KB - 5 downloads)

Zdravstvujte, Vladimir!
1. Verno. Da, 2 i 5 mogut byt' v edinstvennoj pare (ne v diagonal'noj, razumeetsja).
2. Ogranichenij net: v belyh kletkah mogut vstretit'sja ljubye cifry, v tom chisle 2 i 5.

Vyhodit, 2 i 5 - jeto i zerkal'noe otrazhenie i net odnovremenno? ili tol'ko po gorizontali(vertikali)?

Mozhet li 2 byt' v zeljonoj kletke pri otrazhenii vpravo ili vniz ili tol'ko po diagonali?
3 mozhet byt' v zeljonoj kletke TOL''KO pri gorizontal'nom zerkale (vniz-vverh)?

2 zerkal'no otrazhaetsja v 5, esli rech' o sosednih po gorizontali ili vertali poljah. V sebja 2 otrazhaetsja "tol'ko po diagonali".
S 3 vsjo verno.

4 ne mozhet byt' v zeljonoj kletke - neotrazimaja zerkal'no?

Ne mozhet.

I am not able to solve even a single puzzle :(

Read the rules carefully, multiple times.
Try to find openings, applying the rules.
Try to think "If .... then what happens, is any rule violated."
And if you are stuck, save your work and come back later.