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Fivefold Sudoku Test — LMI July Sudoku Test — 16/17th July92 posts • Page 4 of 4 • 1 2 3 4
@ 2011-07-18 10:37 PM (#5239 - in reply to #5237) (#5239) Top

debmohanty




1000500100100100202020
Country : India

debmohanty posted @ 2011-07-18 10:37 PM

David McNeill - 2011-07-18 10:00 PM

(as the pdf file was very slow to open and printing was also incredibly slow).

Really surprised to hear that, because the pdf file size was really small (~100 KB), and all grids were vector based images (except some part of odd-even-big-small).

Did anybody else face the problem?
@ 2011-07-19 11:41 AM (#5240 - in reply to #5239) (#5240) Top

utkaarsh



Posts: 89
20202020
Country : India

utkaarsh posted @ 2011-07-19 11:41 AM

I would second david's point on the fact that puzzles should be sequenced as per points,
but i loved the time based scoring system, knowing your strengths and selecting the right strategy should be rewarded
@ 2011-12-08 9:10 AM (#6160 - in reply to #5092) (#6160) Top

atc121212



Posts: 1

atc121212 posted @ 2011-12-08 9:10 AM

can any body help out for how to start the "crossnumber sudoku and number 5 still alive"?

Edit : Removed a link not related to sudoku / puzzles

Edited by debmohanty 2011-12-08 9:15 AM
@ 2011-12-09 4:11 AM (#6163 - in reply to #6160) (#6163) Top

Valezius



Posts: 66
202020
Country : Hungary

Valezius posted @ 2011-12-09 4:11 AM

atc121212 - 2011-12-08 9:10 AM

can any body help out for how to start the "crossnumber sudoku and number 5 still alive"?

Edit : Removed a link not related to sudoku / puzzles



Crossnumber: There are just 4 3-long and 4-long numbers. Not too hard to find their places. Four instance in the 1st row the 3-long number can be just one from the list.
After the 3-long number in the last row also unique. You can put the other two 3-long number easily.
Now you can find the places of 4-long numbers.


Number 5: A bit harder (it is 78 points)

Four instance in the left-middle box there are 3 cages. The sum 5+5+15 or 5+15+15 But the second isnt good, because the total of remained cells would be 10, and a 6 is given. So it is 1+3+6, but R3C1=3
Hence the correct sum 5+5+15 so this 3 cages contain (2+3) (1+4) (7+8) and the 2 remained cells (5,9)
You can consider the other side as well, the 2 remained cells (1,5)

You could write down numbers, but these are important informations.

If you look at the 5th column you will see 4 cages. The total of this cages 40 or 35 or 30 etc. So 40. And R5C5=5. The number pairs in this column (14) (23) (69) (78) and just one cell can be 9. (R3C5) Now you can find the 9 and 6 in the right-middle box. (5,9) in the left-middle box and (1,5) in the right-middle box. Moreover all 9s unique.

I hope this will be enough.

Fivefold Sudoku Test — LMI July Sudoku Test — 16/17th July92 posts • Page 4 of 4 • 1 2 3 4
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