Richard
Posts: 191
 
Country : The Netherlands | Richard posted @ 2012-07-10 10:39 PM TiiT - 2012-07-10 11:04 AM
In addition, I want to say thanks for the practising material - I solved all of them and It was really useful !!! :)
TiiT
Maybe it's good to write something about the practising material.
A lot of the regular participants in LMI sudoku tests are regular visitors of the puzzle portal of LM Germany and/or do also participate in the German Sudoku championship. So they might be more used to my 'style of puzzle making' (if I have one... ) than others. To give all players the opportunity to practise some more of my puzzles, I think it's fair to provide the links to this practise material.
And meanwhile I hope to attract some players to the puzzle portal Germany too (of course ). There's a lot of very nice puzzles out there, from various authors. (Not only sudokus BTW. )
It's good to read that it's helpful in at least one case!  |
macherlakumar
Posts: 123
Country : India | Nice set of puzzles.
I was able to solve only 4 during the competition, but could not submit the fourth because I ran out of time.
Now I am taking my time to solve other puzzles.
Renban was very good although I have started from the R1 and R3 Renban groups. As you said "What is very helpful for this puzzle is to notice what digits have to be in a renban group, and what digits cannot be in a group", I did the same thing and puzzle was solved very smoothly.
Still more to solve.
Thanks Richard and LMI for wonderful test.
Regards,
Ravi |
gjdv
Posts: 1
Country : The Netherlands | gjdv posted @ 2012-07-12 1:49 AM Let me first thank the author for providing the sudokus.
I'm quite new to these competitions, that might also be why I missed something, as I cannot see why there is a correct solution to one of the simpler sudokus: all odd/even
Let me explain, and hopefully one of you can prove me wrong :)
The grey fields either contain all even or all odd numbers. There are 5 odd numbers (1,3,5,7,9) and 4 even numbers (2,4,6,8) possible. Look at the rightmost column, there are 3 empty grey fields and even numbers 2 and 6 already present. That means that the 3 grey fields in this column cannot be filled with all even numbers (as there are only two left: 4 and 8). Hence, all grey fields should be odd-numbered.
Now look at the second row, there are only two non-grey empty fields, which are located in the top-middle 3x3 square. Number 4 is still missing in this row, hence it should be filled in somewhere in the middle 3, however there is already a 4 present in the top-middle 3x3 square. Hence, the grey fields cannot all be odd-numbered. A contradiction!
edit:
oops... I now see that the restriction on odd/even should be interpreted per 3x3 square... sorry
Edited by gjdv 2012-07-12 2:01 AM
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@ 2012-07-10 10:39 PM (#7787 - in reply to #7775) (#7787) Top