If R6C6 is used by a vertical word,it can be One ,zero,two,six or four.One,two,six fail as it leaves a white space of 2 cells in the top-right corner.Four or zero leave R6C3-4 white,so they fail too.that leaves r6C6 with a horizontal word,which is atleast 4 long to satisfy the black block in the last row.A 4-letter word would leave a V-shaped 5 which leaves a white space in R5 that cant be filled.So only three can use the 6th row.This completes 6 and the entire right half.R1C6 must be black.Done!

Edited by anurag 2012-03-16 5:52 PM

Correct, the rules are badly written

Puzzle Points Group 1. Combined Tapa 154 Puzzles 1-3 2a. Mad Max Tapa 13 Puzzles 1-3 2b. Mad Max Tapa 136 Puzzles 1-3 3. Fractional Tapa 55 Puzzles 1-3 4. Dissected Tapa 63 Puzzles 4-7 5. Visionary Tapa 138 Puzzles 4-7 6. Full Tapa 146 Puzzles 4-7 7. Modern Tapa 43 Puzzles 4-7 8. Power of Tapa 192 Puzzles 8-10 9. Tapa Balance 47 Puzzles 8-10 10. Meiosis Tapa 64 Puzzles 8-10

Announcements Password protected pdf is uploaded. It has 10 pages (including a cover page) Time bonus will be computed after you click "Claim Bonus" Penalty will be given irrespective of correctness of submission Contest Length : 75 minutes Total Points : 1051 Bonus : 10 points per minute saved Grace Period : 5 minutes Penalty : 8 points per minute used (Computed upto seconds)

Last set of practise puzzles are posted. I hope they have been helpful.

http://puzzleparasite.blogspot.com/2012/03/tvc-xi-practise-part-3.h...

Can this question be answered, please? It seems kinda important for the test to know how the answer key works for this particular type. If it's irrelevant because no fractional cells will be in the answer rows and columns that would also help to know.

Edited by Para 2012-03-17 6:37 AM

Para: The test's puzzle did not mark rows or columns with a divided cell, so it's fine. (edit: ok'd to say this by Deb in an email)

Thanks for the great test. As my post in this topic suggested and as my comment on motris's blog made more explicit, I was really worried about the set of variations here, but the test turned out to be the load of fun a TVC usually is. Happy with how I did, but taking it so early means it's a long wait to see how I compare with others...

Edited by MellowMelon 2012-03-17 7:52 AM

Hey it was a wonderful test , after series of screwed performances.
I liked combined tapa and visionary tapa the most.
Thanks for this wonderfull puzzles to LMI and authors.
Initially i was even not able to understand rules of the puzzles, but thanks to Prasanna for clearing doubts and also to Para for practice puzzles..
:) :)

You're welcome.
Well done on the test. Its my turn to have a series of messed up performances now. Hopefully that ends in TVC XII but I guess this puts me back quite a bit. :\ Ah well.

I'm still uncertain about the Ir-irregular Tapa. Especially as the unofficial test puzzle by Para seems to follow different rules!?

Is the following correct: I blacken some areas. Each area has to be either completely black or completely white. When checking the clues and the 2x2-condition the blackened areas are treated as separate black squares.


Regards,

Calavera

Yes, thats right. A 2x1 area for example shall be counted as two cells for clue-counting purposes and a L-shaped Trimino that gets shaded means that 3 cells out of a 2x2 region are shaded. Hope that clears it up.

A beautiful set of puzzles again... Thanks Serkan, you really have the skill of transforming any Tapa variant into a fantastic puzzle grid.

Very enjoyable puzzles, thanks Serkan!

Beautiful puzzles. Wasn't excited when the IB came out but these puzzles were fantastic.

Congratulations again to MellowMelon for winning TVC XI by a huge margin. xevs and deu take 2nd and 3rd position respectively. EKBM also played really well, but had a mistake in one puzzle. Out of 126 players, 109 players got non-zero scores. The table on the right shows cumulative normalized scores of top 10 players.

TVC IX TVC X TVC XI Total MellowMelon 748.2 1000 1000 2748.2 motris 1000 651.5 840.1 2491.6 deu 857.9 643.1 848.1 2349.1 Para 857.9 721 693.8 2272.8 Kota 726.2 836.9 635.5 2198.6 tomek_s 720 586.9 826.9 2133.8 nyuta 681.3 622.4 717 2020.7 xevs 791 313.2 912.1 2016.3 misko 742.2 586.9 684 2013.1 anderson 711.1 589.1 686.7 1986.9

With Serkan not around, I'll put some remarks like he does every time.

There were lot of discomfort among players when the IB was released, must be because of so many new types and some unfamiliar rules. MellowMelon was one of the first players to participate, he had a great performance, but he also posted in forum immediately that the puzzles were nice. Thanks and congratulations for yet another superb performance.

- The puzzle solved by least competitors was Power of Tapa. It was solved by 20 competitors.
- The puzzle solved by most competitors was Fractional Tapa. It was solved by 96 competitors.
- The puzzle with the highest rating was Visionary Tapa (9.28) and the puzzle with the lowest rating was Mad Max Tapa (Top) (6.16).
- The puzzle submitted with the highest accuracy was Dissected Tapa (100%), 64 competitors), lowest was Mad Max Tapa (Bottom) (48.89%, 22/45 competitors)

Here is the link to Cumulative results table - http://logicmastersindia.com/TVC/2012.asp

See you all in the next and final round.

So as I said a few days ago, the test did turn out to be really great. One suggestion I have that would scare everyone less is to not complicate the IB more than it needs to be. Specifically, say up front that the test's Meiosis Tapa would have only even numbers and no multi-number clues. I guess it's possible the IB was released before the puzzle was ready and/or finalized, but that variation as it was in the IB was just plain unwieldy. It's intimidating as hell to have a clue like 1 2 that can function as 1 2, 1 1 1, 1 1, or 1 5 (this possibility eliminates a lot of connectivity logic the clue might have otherwise). The test puzzle itself was great though.

Still not a fan of Mad Max. One good thing about logic puzzles like these is that as hard as solving them can be, checking them is usually easy and straightforward. But for a type like Mad Max, it's almost impossible to be totally sure you have the right answer; computationally, verifying a solution is as hard as solving the puzzle. I think the low success rate on that second puzzle is both not surprising and not a good thing.

I wasn't really enthusiastic at first when I saw the IB, but found enough interesting variants to fill my 75+ minutes after taking a closer look to all the puzzles.
Unfortunately I spent a lot of time on the meiosis tapa, running into contradictions at the same place all the time. I thought to have understand the rules properly, but obviously it's not. So I am very much interested in the solution. If someone can post it here in the forum I would be happy.

Because of the time spent on the meiosis, I just missed the Visionary tapa by a minute. It was a wonderful puzzle, with a brilliant start. Thanks Serkan!

Hi,
Even I have confused myself during the test, but this is a simple puzzle, after the test it took around 8 minutes for me.
I hope the solution is correct.

Regards,
Ravi





Attachments
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Meiosis Tapa.PNG (13KB - 0 downloads)

Thanks!
My problem was the 6 in the middle. If you divide 6 by 2 yo get 3, not 3/3. So I assumed I did something wrong but didn't know what.
As far as I can see, the IB doesn't contain an example where an even digit gives a two-clue digit after dividing.

Did anyone else have problems with this or is it just me who can't read?

Hi,
Para has explained by taking 2 2 as an example in this thread, probably you might have missed it.
http://logicmastersindia.com/forum/forums/thread-view.asp?tid=458&start=23

Regards,
Ravi

Thanks again for the many fun puzzles, Serkan!

I'd be interested in seeing the solution to the Mad Max Tapa. I wasn't confident in my solution being optimal and didn't want to risk losing points submitting after the 75 minutes expired (even though it was only 5 seconds), which is why I only submitted for 10 puzzles and not 11. If there's some logic involved in confirming the maximum that would also be nice to know. I was hoping for some kind of logic that I had in mine, but I couldn't really find any.

I just solved this one after the fact. There was far more pure Tapa solving to do than I could see during the contest… The picture I intend to attach shows how far I could get just with Tapa deductions. At that point, you can shade in all cells that don't neighbour clues and complete this to a solution that also maximizes the clued cells (around the 6,3,23,11 chain).






Attachments
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madmax.png (19KB - 3 downloads)

I also solved it in the aftermath. The factor which makes the solution unique is column 1.
You have to connect the upper part with the bottom part. You can't do it on the right hand side because of the pait (11). If you do it in column 1 if you blacken R7 and R8 you lose the opportunity to blacken R10 and R11.
If you blacken R7, R10 and R11 you blacken 3 cells insted of 2, and you can still connect top and bottom through R8C7 and R6C10, and this also gives a unique solution for the (11) pair in R3C11

For Mad Max, I did not get as much in the top as rob has in that image, but I had the rest. When I was stuck there I decided I would try to shade in all the unclued squares, save for the top left where at least one had to be left white, and see if that worked. Wasn't 100% sure though when I was done, since it could have been possible to squeeze out more by leaving more squares at the intersections of clues unshaded. I eventually convinced myself that there was no way a puzzle in a timed contest could be that cruel to have the valid and fairly well-constrained solution I had found and not have it be right, but it was a doubt I had even as I went to claim time bonus...

By the way rob, why didn't you shade R10C6 and R10C11? =P