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auroux
Posts: 145
 
Country : France | auroux posted @ 2023-04-16 11:53 AM Now that the contest has started, is the puzzle booklet coming soon? |
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Puzlifouk
Posts: 67
Country : France | Hi everybody,
What is going on with this contest? It seems open, but without a puzzle booklet, it is effectively closed. And the messages in the discussion thread are not readable, even when you are logged in. Can we have some information? |
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puzzler05
Posts: 7
Country : South Korea | still+no+booklet.... |
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prasanna16391
Posts: 1801
 
Country : India | Note: Sorry about the puzzle booklet. I missed a command that shows it. Its up now. I'll extend the contest end by a day to compensate. |
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Puzlifouk
Posts: 67
Country : France | Hello again. For puzzle 9 (Open road): Do you confirm not all double cells must have a one-half shaded? |
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auroux
Posts: 145
Country : France | auroux posted @ 2023-04-16 6:36 PM For+puzzle+2%2c+the+answer+key+of+the+example+seems+wrong+(should+be+WWWIW). |
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Administrator
Country : India | I confirm the other way: all double cells must have one half shaded and the other used. |
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Administrator
Country : India | Auroux: You are right. The answer key for example 2 is wrong and there should be an I instead of an L. |
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Puzlifouk
Posts: 67
Country : France | OK! So that means half shaded cell may touch a shaded cell, at least diagonally!
In fact, my initial problem was that I inderstood ths conditions as :
- all double cells must have a shaded half and an unshaded half;
- all shaded cells and all shaded half of double cells do not touch.
But these two conditions cannot both be verified. If they were, this creates problem around the magenta and the lemon M.
So I have a new question: if a shaded half of a double celle can touch a shaded cell (or another shaded half of a double cell), is it necessarily diagonally, or can it also be orthogonally? Am I clear? |
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Administrator
Country : India | Shaded cells cannot touch orthogonally. They can touch diagonally. (This is for puzzle 9) |
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Puzlifouk
Posts: 67
Country : France | Administrator - 2023-04-16 7:43 PM
Shaded cells cannot touch orthogonally. They can touch diagonally. (This is for puzzle 9)
OK Thanks. The puzzle booklet says something else ("The shaded cells do not touch, not even diagonally" ). It will be corrected, I suppose ... |
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Administrator
Country : India | Yes we will get it corrected soon. |
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Administrator
Country : India | |
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Puzlifouk
Posts: 67
Country : France | Hello. New question about problem 10. What is the order of priority of the operations? Are the operations performed in the order they are found or do multiplication (X) and division (/) have priority? In other words, do we have 9-6/3=(9-6)/3=1 or 9-6/3=9-(6/3)=7? |
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prasanna16391
Posts: 1801
Country : India | The rules say "without parenthesis" which means they are performed in the order they are found. |
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Barbitos
Posts: 6
Country : France | %5BQUOTE%5D8%2E+There+shall+be+no+online+solving+interface+%28like+penpa%29+provided+for+this+test%2E%5B%2FQUOTE%5D%0D%0A%0D%0AAre+we+still+allowed+to+use+penpa+to+copy+the+puzzles+and+solve+them+if+we%27re+more+confortable+with+it%3F%0D%0A%0D%0AAlso%2C+to+what+extent+are+we+allowed+to+use+calculators+and+other+programs%3F+I%27m+guessing+the+line+is+drawn+at+something+like+%22only+what+you+could+do+on+windows%27+calculator+app%22+or+%22no+calculators+allowed+period%22%0D%0A%0D%0AI+couldn%27t+find+any+clear+ruleset+for+this+contest%2C+if+there+are+i+would+like+to+know+where+it+is+%F0%9F%98%8A |
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Riad Khanmagomedov
Posts: 234
Country : Russia | Puzlifouk - 2023-04-17 11:50 AM
Hello. New question about problem 10. What is the order of priority of the operations? Are the operations performed in the order they are found or do multiplication (X) and division (/) have priority? In other words, do we have 9-6/3=(9-6)/3=1 or 9-6/3=9-(6/3)=7?
9-6/3=7. The priority of operations is standard. |
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prasanna16391
Posts: 1801
Country : India | prasanna16391 - 2023-04-17 2:36 PM
The rules say "without parenthesis" which means they are performed in the order they are found.
Sorry, guess I was a bit wrong here, please follow what Riad says. |
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prasanna16391
Posts: 1801
Country : India | %5BQUOTE%5DBarbitos+%2D+2023%2D04%2D17++6%3A11+PM%0D%0A%0D%0AAre+we+still+allowed+to+use+penpa+to+copy+the+puzzles+and+solve+them+if+we%27re+more+confortable+with+it%3F%0D%0A%0D%0AAlso%2C+to+what+extent+are+we+allowed+to+use+calculators+and+other+programs%3F+I%27m+guessing+the+line+is+drawn+at+something+like+%22only+what+you+could+do+on+windows%27+calculator+app%22+or+%22no+calculators+allowed+period%22%0D%0A%0D%0AI+couldn%27t+find+any+clear+ruleset+for+this+contest%2C+if+there+are+i+would+like+to+know+where+it+is+%F0%9F%98%8A%5B%2FQUOTE%5D%0D%0A%0D%0ARedrawing+on+Penpa+is+fine%2E+There+is+no+rule+against+using+calculators+and+other+programs%2C+but+the+contest+was+intended+to+be+done+without+them%2E+I+suppose+your+line+is+a+good+line+to+draw%2E+ |
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auroux
Posts: 145
Country : France | auroux posted @ 2023-04-17 8:54 PM On puzzle 10, does a circular equality loop "all around" with equal signs separating equal terms (in particular there must be at least two = signs), or do we get to "break the circle" where we want (not necessarily at an equality sign, and not necessarily in the same place in both directions) to form equalities that can be read clockwise or counterclockwise?
Concretely, if for some digits A,B,C,D,E one had the identities A_PLUS_BC=DEF and ED=CB_PLUS_AF, where the latter can be formed by writing the former around a circle, cutting in a different place, and reading in the other direction, would this be a valid solution ? Or is the only legal way to write the identity A_PLUS_BC=DEF to actually write "A_PLUS_BC=DEF=" around the circle (with an extra equal sign) and both expressions must be formed by cutting the circle at an "=" sign ?
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auroux
Posts: 145
Country : France | auroux posted @ 2023-04-17 8:59 PM After more thinking, I assume the correct interpretation is that we can break the circle anywhere we want (not necessarily at an = sign, and not necessarily in the same place in both directions), and that the example I gave would be a valid solution. Otherwise, it would have been easier to state the problem as producing an equality which is valid when read forwards and backwards (no need to use a circle). |
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jeff10
Posts: 1
Country : United States | jeff10 posted @ 2023-04-17 9:26 PM For the Bubbles Puzzle (Puzzle 2), do bubbles have to circle completely around an NxN (N=1,2,3) square of cells, or can a bubble of "size 3" only circle 3 of the leftmost cells while the center of the bubble is outside the grid? |
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Riad Khanmagomedov
Posts: 234
Country : Russia | auroux - 2023-04-17 8:54 PM
On puzzle 10, does a circular equality loop "all around" with equal signs separating equal terms (in particular there must be at least two = signs), or do we get to "break the circle" where we want (not necessarily at an equality sign, and not necessarily in the same place in both directions) to form equalities that can be read clockwise or counterclockwise?
Concretely, if for some digits A,B,C,D,E one had the identities A_PLUS_BC=DEF and ED=CB_PLUS_AF, where the latter can be formed by writing the former around a circle, cutting in a different place, and reading in the other direction, would this be a valid solution ? Or is the only legal way to write the identity A_PLUS_BC=DEF to actually write "A_PLUS_BC=DEF=" around the circle (with an extra equal sign) and both expressions must be formed by cutting the circle at an "=" sign ?
You can't break the expression wherever you want. If you write down your expressions many times in a row (or read in a circle an infinite number of times ), then you should get the right equality. In the example , you can write 68=45_PLUS_23=68=45_PLUS_23=68= etc. |
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Riad Khanmagomedov
Posts: 234
Country : Russia | auroux - 2023-04-17 8:59 PM
After more thinking, I assume the correct interpretation is that we can break the circle anywhere we want (not necessarily at an = sign, and not necessarily in the same place in both directions), and that the example I gave would be a valid solution. Otherwise, it would have been easier to state the problem as producing an equality which is valid when read forwards and backwards (no need to use a circle).
The circle is used in the construction of letter palindromes, which are read an infinite number of times clockwise and counterclockwise, but sometimes giving different phrases. In Russia, such constructions are called cyclodromes. |
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auroux
Posts: 145
Country : France | auroux posted @ 2023-04-18 12:21 AM Riad Khanmagomedov - 2023-04-17 11:06 AMYou can't break the expression wherever you want. If you write down your expressions many times in a row (or read in a circle an infinite number of times), then you should get the right equality. In the example , you can write 68=45_PLUS_23=68=45_PLUS_23=68= etc.
Ok, thanks. But, uh, wait. Now I am concerned. Is there, then, a requirement to have at least two equal signs?
Otherwise, something like '98765*43210=' around the circle produces a valid equality when reading around the circle infinitely many times: 98765*43210=98765*43210=98765*43210=...
But this seems to violate the spirit of the puzzle, or at least there isn't much optimization left to do in this version.
And for completeness, can you clarify what exactly you expect in the answer key? The example given for the answer format only has one = sign given for each direction, even though there are two reading around the circle, so do we answer by giving what you get by cutting the circle open at an '=' sign and reading everything from just after that '=' sign to just before it, but not including the '=' sign along which we cut?
Sorry to be picky about details, but I think people spending time on this puzzle want to make sure that they are working on the correct version of it...
Thanks,Denis |
@ 2023-04-16 11:53 AM (#31453 - in reply to #31435) (#31453) Top