Since 5 is already there in either R1C9 or R2C9, we have R5C9 = 9 and R5C8 = 5. this allows us also to fill R9C8 = 4 and R9C9 = 8 and also R6C9 = 7.

So till now we have used 1,2,14,15,18 and 20 of the missing sums. We are now left with 3,4,7,9,11,12,13,16,17,19.



Edited by Rohan Rao 2012-05-27 5:21 PM

in Box 9, we already have 2 cages with combined sum of 16. Hence the other 2 cages with missing sums add upto 29. From the remaining sums this 29 can either be 17,12 or 13,16. the pair of 12,17 is eliminated as the 2 cell cage cannot be 17 since 8 is already there in R9C9 and it cannot be 12 also since one of the numbers in 6. Hence the 2 cell cage has a missing sum of 13 (6,7) and the 3 cell cage has sum of 16 (2,5,9).

so now we are left with missings sums of 3,4,7,9,11,12,17,19.

I guess from here on the puzzle solves logically :) but if anyone wants me to continue I will be glad to do it.

Rishi

thanks for the steps rishi. The puzzle is indeed very beautiful, both the concept and the particular puzzle.

this is grt!!!!!!!!!

rishi,
hi.my name is dhaval.i m abig fan of yours.but this killer sudoku is easy as it contains one cell sum like 3 and 6 .can u explain a difficult one completely?please. i m a starter. also i find killer sudokus tough. so please can u explain a more difficult one and in easy langusge just like above one. it would be helpful to everyone.pls!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

rishi.
also please can u solve the sudoku completely which u left above and explain it.pls!!!!!!!!!!!!!!!!!!
i know i m asking tooo much.ut plaese rishi sir!!!!!!!!!!!!!!!!!!!!!!!!!