Hi,
Welcome to LMI
There is no other process for participating in Indian Puzzle Championship (IPC), registering at LMI is sufficient to participate.
Please do not open any new threads for IPC 2013 related things, follow/post queries in this thread of IPC 2013.

Regards,
Ravi

how to register for ipc 2013 ? whether the test can also be taken offline ?

please help i am a new user ....

You're already registered for LMI, so there's nothing you have to do other than watch this topic for the Submission link, and then login (with this same "inventor" user name) and participate..

Hi,
Your question is already answered here.
The contest is not conducted offline. It is conducted online which means you have to take print out of the puzzle booklet and enter the answers at the link provided.
Watch this thread for more information.

Regards,
Ravi

hello
when the ipc will start and what is the duration of the test ?

This information is already given earlier in this thread - "2pm on the specified day"


This will be announced soon. But since the format is similar to last year, it could be about 2.5 hours duration.

By 2pm, in what timezone? (I think the answer is "Indian Standard Time" which Wikipedia says to be UTC+05.30 (aka the time is 08.30 am UTC), but just want to make sure.)

Also, I assume that this is not like other puzzle tests where you have a 48-hour window or something to start? (As in you must start at 2pm; if you're late, you lose the lost time?)

Usually (last year is an example, scroll down in the link provided above to see the unofficial Rest-of-the-world results), although the IPC is at a fixed time for all Indian participants, it is extended thereafter for international players to participate. Hopefully, the format is similar this year.

hi
please help me for getting the solution of ipc 2010.
thanking you

Please post specific puzzle for which you need solution. Making solutions for all puzzles will take time for us.

Another way to go about it is, if you want to check your solutions from solving those puzzles, you can just post your solution images here, and we'll confirm if they are right or not. You can also post incomplete puzzles here if you are stuck and want us to tell you the next step in order to proceed. :)

hi
thanks for the reply.
i am post my problems here.
hoping for a favorable reply :)
Ipc 2009
Minesweeper:
I can’t understand the meaning of the last line “when all the four grids are solved single coordinate should exactly contain one mine”.
Dominos:
How to solve these type of problem?
What should be the first step of approach solve the probem?
Please help.
No four in a row;
How to solve these type of problem?
What should be the first step of approach solve the probem?
Please help.
Is more than one answer possible??
Ripple effect :
Please check the last row of the answer it’s not following the question rule that if same digit appears then they should be separated by cells equal to the digit. {for 1}
Triangle count:
I got a max. 31 triangles on many attempts.
Is the answer given 32 correct?
Trid:
How to solve these type of problem?
What should be the first step of approach solve the probem?
Please help.
Polygraph:
How to solve these type of problem?
What should be the first step of approach solve the probem?
Please help.

I'll deal with your queries one at a time. If you see the example in the Instruction booklet, you will see the letters A-H, and in the competition puzzle, you will see 1-4 at the bottom and A-D on the side. This is basically an easy way to name the rows and columns. So, I'll explain using the competition puzzle. In each 4x4 grid, take the first row as "3" and 1st column as "A". So, the intersection of these will be one cell, the cell that is left-most in the 3rd row, and this cell can be called A3 for reference. So in all 4 grids, A3 can have a mine in at most just one grid. (below is an image showing A3 for 2 of the grids, you'll need to use this co-ordination for all 4)





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2.png (6KB - 2 downloads)

I usually use a few basic tricks, like say, search for some pair that has only one instance in the entire grid. In the competition puzzle, one of those pairs is 0-2 I think, so I've marked it.

That could be time consuming, so sometimes things can be found in the corners, like if there's something like

1 2 _ _
2 _ _ _

in a corner, you know that, whichever way the 1 is paired, it has to be paired with 2, so you can then divide all borders in the rest of the grid where 2 and 1 are next to each other.

In the particular competition puzzle of 2010, there's another little trick - Right at the top, if the 5 to the right of the 2 pairs up with the 3 below, then that results in another 3-5 pairing to the right of that, considering all numbers need to be paired (Rules say layout is showed with domino edges removed, so everything's part of a domino). So, the 5 pairs up with the 2.

I've also marked below a border above a 1 that I haven't explained. The explanation for that is, there's three 1s there, and that is the only place where 1-1 pairing can be done. So that 1 will be paired rightward or downward, so can't go upward/leftward, hence the line above it.

Domino's not one of my good types though, so I might have missed some key points. But once you start spotting these techniques you could tend to ease into whats needed to solve it.





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Domino.png (51KB - 2 downloads)

Firstly, unless explicitly mentioned otherwise, all puzzles have exactly one solution only. As for how to start, just look at 4 consecutive cells in a row/column/diagonal where 3 are already given and are all X (or all O). Then the 4th cell in that row/column/diagonal must be the other sign (Not the one given in all the other 3). If you start at these places, that forms other places where this happens and so on and you can go on solving like that and reach the single solution.

For the competition puzzle in 2009, see the 3rd row, there's an X in the 1st, 2nd and 4th cell. So, by the above explanation, the 3rd cell has to be O, else there'd be 4 Xs in a row.

For the Ripple Effect - I don't get exactly what you mean. Do you mean that the 1s are touching diagonally? If so, they can be next to each other diagonally, the rule only states "same row or column". If you mean something else, is it possible to be clearer? (Maybe post a picture).

For Triangle Count - Given that multiple participants have participated in that Championship that year, if there is any problem, it'd already be reported mostly :) I'm guessing, you might have missed the hidden big triangle, pointing downwards? (There's one big traingle pointing upwards and one of that same size pointing downwards).

For Trid - Consider that digits can't repeat in any straight line. Now look at the competition puzzle, see the "6" sum. The only numbers that can come around it, due to no-repeat rule, are 1,2,3. Since the digit set is 1-6, the maximum sum that 2 adjacent cells can have is 11 (6+5), so the 14 next to the 6 has to have a 3 in the one circle they share, because otherwise, you need more than 11 in the other 2 cells which isn't possible. Use such things, and Sudoku-type eliminations along the straight lines, and you'll get there.

The easiest way to start the competition puzzle of 2009 is to use the 0. Think of it this way - Every cell has a total of 4 lines that can be around it. But no clue can have all 4 lines around it used, because that'll form a little square loop away from the main loop. So, a 0 has to be the number of lines used, rather than unused, because if 0 lines are unused, that means 4 lines are used. Therefore, all 0s have to be inside the loop and have no lines around them. Since the 0 is inside the loop, there needs to be some part of the loop "binding" it on all sides. so, you have a line in the last row, under the 0. This means, the 3 is "bound" as well and is also inside the loop, and there's your start, and you can now also prove that the two 1s are outside the loop and this means that 3 sides of theirs are used by the loop.







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Polygraph.png (29KB - 0 downloads)

thank you very much prasanna for your valuable reply. :)

hey tel m details dude

By "IPC will be open for a longer period for international players to participate at their own convenience." (IB), what or how long exactly is the period? Can we assume that it's at least 24 hours?

EDIT: More questions as I'm reading the IB:

In F1-F2, can we assume the circle marked A is aligned to some edge of the grid? (This makes seeing which way is clockwise to become easier. Related post.)

In H2, can we assume that we're told which squares are blank? (Just in case the grid is actually a cross or some other thing that is not a rectangle; if we're not told so, the spaces outside the grid can be either a blank square that is supposed to be filled or simply not part of the grid. Currently, the example in the IB has an outlined grid, so the part inside the grid is visible.)



Edited by chaotic_iak 2013-06-30 2:30 PM

For International participation, IPC will be open for 48 hours. When flash submissionis enabled - in a few days from now, local times will be displayed.

"A" will always be the first (top-left-most) black circle. Letters will be marked only on black circle.
However, full points will be awarded if you start from any given letter, and go clock wise / anti clock wise - as long as you enter all letters you should be safe.

Just like the IB, the final puzzle will be a square with borders.

One note about answer key of Battleships :
Answer Key: For each row from top to bottom, enter the column position of left most ship segment. Enter X if no ships.

The word "segment" was missing from the IB.

1. If I understand it right, the A1 questions will be different versions of the ones given in the Instructions booklet, but A2 will be unknown types?

2. Will the Skyscraper Sudoku be a 9x9 or something smaller?

Yes.
Smaller.