@ 2010-11-08 8:59 AM (#2416 - in reply to #2414) (#2416) Top | |
Posts: 14 Country : China | cpickerel posted @ 2010-11-08 8:59 AM This is the author's algorithm; other players are more than welcome to contribute to additional solutions. |
@ 2010-11-08 10:34 AM (#2418 - in reply to #2416) (#2418) Top | |
Posts: 460 Country : India | purifire posted @ 2010-11-08 10:34 AM cpickerel - 2010-11-08 8:59 AM This is the author's algorithm; other players are more than welcome to contribute to additional solutions. Lovely explanation Chen Cen.... However, when I solved, I deviated from step 7 onwards... Steps 1 to 6 are exactly as you explained... I will continue from step 7 onwards an alternate route to solve this.... -------------------------------------------- R9C5 has to be an odd number since the 4 is in R7C5 and no other even number can precede it .... 1,5,9 are eliminated due to normal sudoku rules... 7 has to be a part of R8C6 or R9C6 since R6C6 is a 9 and no odd number can precede 7 in column six via the constraints of box 8. Hence R9C5 is a 3. Similarly 2 has to be in R9C4. (OStep7.png) Attachments ---------------- OStep7.png (32KB - 1 downloads) |
@ 2010-11-08 10:44 AM (#2419 - in reply to #2418) (#2419) Top | |
Posts: 460 Country : India | purifire posted @ 2010-11-08 10:44 AM Now in Box 9, the numbers 8 and 9 are in R7C7 or R8C7 or R9C7.... this allows for a naked single 7 in R9C8. Based on this we fill up the 8 and 9 also in Row 9. R9C6=8 and R9C7=9. Entire Box 9 can be filled now. R8C7=8, R7C7=3 and R8C8=4 by normal sudoku rules. This allows for R7C8=6 as per constraints of Box 9 and finally R8C9=5. (OStep8.png) Attachments ---------------- OStep8.png (36KB - 0 downloads) |
@ 2010-11-08 11:02 AM (#2420 - in reply to #2419) (#2420) Top | |
Posts: 460 Country : India | purifire posted @ 2010-11-08 11:02 AM Again based on normal sudoku rules, we also fill up the entire Box 8. R7C4=9, R7C6=5, R8C6=7, R8C4=6. (OStep9.png) Attachments ---------------- OStep9.png (37KB - 0 downloads) |
@ 2010-11-08 11:07 AM (#2421 - in reply to #2420) (#2421) Top | |
Posts: 460 Country : India | purifire posted @ 2010-11-08 11:07 AM Now in Box 6, the middle row has a sum of 22 which can only be either 9,6,7 or 9,8,5. since 6 and 7 are already present in Column 8, the middle row has to be 9,8,5. By normal sudoku rules, R5C8=8,R5C7=5,R3C8=5,R4C3=8, R4C8=2. By constraints of Box 4, R5C1 has to be a 7. (OStep10.png) Attachments ---------------- OStep10.png (40KB - 1 downloads) |
@ 2010-11-08 11:11 AM (#2422 - in reply to #2421) (#2422) Top | |
Posts: 460 Country : India | purifire posted @ 2010-11-08 11:11 AM After step 10, since all external constraints are satisfied, the present grid can be solved logically as any other classic sudoku. Hope this was helpful. Rishi (purifire) |
@ 2010-11-08 4:52 PM (#2425 - in reply to #2409) (#2425) Top | |
Country : India | debmohanty posted @ 2010-11-08 4:52 PM Thanks cpickerel and Rishi for the detailed writeup with images. RJH0723, hope that was useful to you. |
@ 2010-11-09 2:30 AM (#2433 - in reply to #2409) (#2433) Top | |
Posts: 13 Country : United States | RJH0723 posted @ 2010-11-09 2:30 AM Thanks Guys. That helped a lot. The key thing I missed was the R6 skyscraper constraint. That would have enabled me to finish it. You guys are the best! |
@ 2010-11-09 11:10 PM (#2449 - in reply to #2433) (#2449) Top | |
Posts: 460 Country : India | purifire posted @ 2010-11-09 11:10 PM RJH0723 - 2010-11-09 2:30 AM Thanks Guys. That helped a lot. The key thing I missed was the R6 skyscraper constraint. That would have enabled me to finish it. You guys are the best! Glad this was helpful.... Rishi |