In Center Box there are only two possibilities of 9 i.e. R4C6 and R6C6.
Putting 9 in R4C6 will force R6C7 to be 9 and Putting 9 in R6C6 will force R5C9 to be 9. In both the cases R4C7,R4C8 and R6C2 cannot have 9?
Stuck in Antidiagonal sudoku4 posts • Page 1 of 1 • 1
@ 2016-04-01 11:35 PM (#21419 - in reply to #21414) (#21419) Top
