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Vishal
Posts: 22
Country : India | Vishal posted @ 2016-03-19 11:21 AM Anyone, please help me with this sudoku; I'm unable to proceed further
I'm trying to attach the image file, but the attempt is getting failed again and again (file size is 37 KB)
Edited by Vishal 2016-03-19 11:27 AM
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prasanna16391
Posts: 1784
Country : India | Try uploading on an image hosting site and sharing the link. |
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Vishal
Posts: 22
Country : India | Vishal posted @ 2016-03-19 2:13 PM |
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kishy72
Posts: 417
Country : India | kishy72 posted @ 2016-03-19 2:42 PM
6 in R4C6 means a 6 in R1C4 or R3C4 which takes off a 6 from R8C4 .Hence for the 8th row,you have a pair (48 )in R8C1 and R8C4 ---->R8C8 becomes a 6 . |
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Vishal
Posts: 22
Country : India | Vishal posted @ 2016-03-19 3:48 PM |
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prasanna16391
Posts: 1784
Country : India | For the first one, if 2 is in R5C1, it will have to be in C5 for both R4 and R9. So, 2 cannot be in R5C1. |
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Vishal
Posts: 22
Country : India | Vishal posted @ 2016-03-20 10:30 AM Thanks Prasanna
I got what you're saying....but, I want to confirm that is that a logical way?? I mean, in this case one have to assume and deduce if 2 were to come in R2C1 then after 3-4 steps it would be a contradiction...
Though I myself use the aforesaid technique but I'm not sure about its rationality. |
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Vishal
Posts: 22
Country : India | Vishal posted @ 2016-03-20 10:31 AM kishy72 - 2016-03-19 2:42 PM
6 in R4C6 means a 6 in R1C4 or R3C4 which takes off a 6 from R8C4 .Hence for the 8th row,you have a pair (48 )in R8C1 and R8C4 ---->R8C8 becomes a 6 .
Thanks Kishore |
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Vishal
Posts: 22
Country : India | Vishal posted @ 2016-03-23 6:10 PM Stuck here...anyone please guide through next steps.
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dp_94
Posts: 25
Country : India | dp_94 posted @ 2016-03-23 7:11 PM |
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Vishal
Posts: 22
Country : India | Vishal posted @ 2016-03-24 11:26 AM
Thanks @dp_94.
All the things you mentioned are really helpful in giving me a boost. |